Question

chemistry: ions in chemical compounds
name: micah carter
hour: 7 date: 9/20/25
complete the following table, being sure that the total charge on the resulting compound is zero.

ions	chloride cl⁻	hydroxide oh⁻	nitrate no₃⁻	sulfate so₄²⁻	sulfide s²⁻	carbonate co₃²⁻	phosphate po₄³⁻
sodium na⁺	nacl	naoh	nano₃
ammonium nh₄⁺	nh₄cl	nh₄oh	nh₄no₃
potassium k⁺	kcl	koh	kno₃
calcium ca²⁺	cacl₂	ca(oh)₂	ca(no₃)₂
magnesium mg²⁺	mgcl₂	mg(oh)₂	mg(no₃)₂
aluminum al³⁺	alcl₃	al(oh)₃	al(no₃)₃
iron (ii) fe²⁺
iron (iii) fe³⁺	fecl₃	fe(oh)₃
copper (i) cu⁺	cucl	cuoh

Explanation:

Step1: Determine compound formulas

For each pair of cations and anions, balance the charges to form a neutral - charge compound. For example, when a calcium ion ($Ca^{2 + }$) combines with a sulfate ion ($SO_{4}^{2 - }$), the formula is $CaSO_{4}$ because the + 2 charge of calcium balances the - 2 charge of sulfate.

Step2: Write formulas systematically

Go through each row (cation) and column (anion) combination. For a hydrogen ion ($H^{+}$) and a carbonate ion ($CO_{3}^{2 - }$), two hydrogen ions are needed to balance the - 2 charge of the carbonate ion, so the formula is $H_{2}CO_{3}$.

Answer:

Ions	Chloride $Cl^{-}$	Hydroxide $OH^{-}$	Nitrate $NO_{3}^{-}$	Sulfate $SO_{4}^{2 - }$	Sulfide $S^{2 - }$	Carbonate $CO_{3}^{2 - }$	Phosphate $PO_{4}^{3 - }$
Sodium $Na^{+}$	$NaCl$	$NaOH$	$NaNO_{3}$	$Na_{2}SO_{4}$	$Na_{2}S$	$Na_{2}CO_{3}$	$Na_{3}PO_{4}$
Ammonium $NH_{4}^{+}$	$NH_{4}Cl$	$NH_{4}OH$ (usually written as $NH_{3}\cdot H_{2}O$)	$NH_{4}NO_{3}$	$(NH_{4})_{2}SO_{4}$	$(NH_{4})_{2}S$	$(NH_{4})_{2}CO_{3}$	$(NH_{4})_{3}PO_{4}$
Potassium $K^{+}$	$KCl$	$KOH$	$KNO_{3}$	$K_{2}SO_{4}$	$K_{2}S$	$K_{2}CO_{3}$	$K_{3}PO_{4}$
Calcium $Ca^{2 + }$	$CaCl_{2}$	$Ca(OH)_{2}$	$Ca(NO_{3})_{2}$	$CaSO_{4}$	$CaS$	$CaCO_{3}$	$Ca_{3}(PO_{4})_{2}$
Magnesium $Mg^{2 + }$	$MgCl_{2}$	$Mg(OH)_{2}$	$Mg(NO_{3})_{2}$	$MgSO_{4}$	$MgS$	$MgCO_{3}$	$Mg_{3}(PO_{4})_{2}$
Aluminum $Al^{3 + }$	$AlCl_{3}$	$Al(OH)_{3}$	$Al(NO_{3})_{3}$	$Al_{2}(SO_{4})_{3}$	$Al_{2}S_{3}$	$Al_{2}(CO_{3})_{3}$	$AlPO_{4}$
Iron (II) $Fe^{2 + }$	$FeCl_{2}$	$Fe(OH)_{2}$	$Fe(NO_{3})_{2}$	$FeSO_{4}$	$FeS$	$FeCO_{3}$	$Fe_{3}(PO_{4})_{2}$
Iron (III) $Fe^{3 + }$	$FeCl_{3}$	$Fe(OH)_{3}$	$Fe(NO_{3})_{3}$	$Fe_{2}(SO_{4})_{3}$	$Fe_{2}S_{3}$	$Fe_{2}(CO_{3})_{3}$	$FePO_{4}$
Copper (I) $Cu^{+}$	$CuCl$	$CuOH$ (unstable, usually forms $Cu_{2}O$ and $H_{2}O$ in solution)	$CuNO_{3}$	$Cu_{2}SO_{4}$	$Cu_{2}S$	$Cu_{2}CO_{3}$	$Cu_{3}PO_{4}$