QUESTION IMAGE
Question
chemistry single replacement reaction worksheet
using the activity series table, complete the following reactions by writing the products that are formed. be sure to balance each equation. if no single replacement reaction occurs, write nr to the right of the arrow.
- $ag + kno_3 \to$ noreaction
- $zn + agno_3 \to$
- $al + h_2so_4 \to$
- $cl_2 + ki \to$
- $li + h_2o \to$
- $cu + feso_4 \to$
- $na + h_2o \to$
- $fe + pb(no_3)_2 \to$
- $cu + h_2o \to$
- $cu + al_2(so_4) \to$
- $al + pb(no_3)_2 \to$
- $cl_2 + nai \to$
- $fe + agch_3coo \to$
- $al + cucl_2 \to$
- $br_2 + cai_2 \to$
- $al + hcl \to$
- $mg + hcl \to$
- $zn + h_2so_4 \to$
- $fe + cuso_4 \to$
- $cl_2 + mgi_2 \to$
Step1: Check reactivity, predict products
For each reaction, use the activity series: a more reactive element replaces a less reactive one in a compound.
Step2: Balance the chemical equation
Adjust coefficients to equalize atom counts on both sides. If no reaction (less reactive element can't replace a more reactive one), write NR.
---
- $\text{Ag} + \text{KNO}_3
ightarrow \text{NR}$
(Ag is less reactive than K, no reaction)
- $\text{Zn} + 2\text{AgNO}_3
ightarrow \text{Zn(NO}_3\text{)}_2 + 2\text{Ag}$
- $2\text{Al} + 3\text{H}_2\text{SO}_4
ightarrow \text{Al}_2(\text{SO}_4)_3 + 3\text{H}_2$
- $\text{Cl}_2 + 2\text{KI}
ightarrow 2\text{KCl} + \text{I}_2$
- $2\text{Li} + 2\text{H}_2\text{O}
ightarrow 2\text{LiOH} + \text{H}_2$
- $\text{Cu} + \text{FeSO}_4
ightarrow \text{NR}$
(Cu is less reactive than Fe, no reaction)
- $2\text{Na} + 2\text{H}_2\text{O}
ightarrow 2\text{NaOH} + \text{H}_2$
- $\text{Fe} + \text{Pb(NO}_3\text{)}_2
ightarrow \text{Fe(NO}_3\text{)}_2 + \text{Pb}$
- $\text{Cu} + \text{H}_2\text{O}
ightarrow \text{NR}$
(Cu is less reactive than H, no reaction with water)
- $\text{Cu} + \text{Al}_2(\text{SO}_4)_3
ightarrow \text{NR}$
(Cu is less reactive than Al, no reaction)
- $2\text{Al} + 3\text{Pb(NO}_3\text{)}_2
ightarrow 2\text{Al(NO}_3\text{)}_3 + 3\text{Pb}$
- $\text{Cl}_2 + 2\text{NaI}
ightarrow 2\text{NaCl} + \text{I}_2$
- $\text{Fe} + 2\text{AgCH}_3\text{COO}
ightarrow \text{Fe(CH}_3\text{COO)}_2 + 2\text{Ag}$
- $2\text{Al} + 3\text{CuCl}_2
ightarrow 2\text{AlCl}_3 + 3\text{Cu}$
- $\text{Br}_2 + \text{CaI}_2
ightarrow \text{CaBr}_2 + \text{I}_2$
- $2\text{Al} + 6\text{HCl}
ightarrow 2\text{AlCl}_3 + 3\text{H}_2$
- $\text{Mg} + 2\text{HCl}
ightarrow \text{MgCl}_2 + \text{H}_2$
- $\text{Zn} + \text{H}_2\text{SO}_4
ightarrow \text{ZnSO}_4 + \text{H}_2$
- $\text{Fe} + \text{CuSO}_4
ightarrow \text{FeSO}_4 + \text{Cu}$
- $\text{Cl}_2 + \text{MgI}_2
ightarrow \text{MgCl}_2 + \text{I}_2$
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- $\text{Ag} + \text{KNO}_3
ightarrow \text{NR}$
- $\text{Zn} + 2\text{AgNO}_3
ightarrow \text{Zn(NO}_3\text{)}_2 + 2\text{Ag}$
- $2\text{Al} + 3\text{H}_2\text{SO}_4
ightarrow \text{Al}_2(\text{SO}_4)_3 + 3\text{H}_2$
- $\text{Cl}_2 + 2\text{KI}
ightarrow 2\text{KCl} + \text{I}_2$
- $2\text{Li} + 2\text{H}_2\text{O}
ightarrow 2\text{LiOH} + \text{H}_2$
- $\text{Cu} + \text{FeSO}_4
ightarrow \text{NR}$
- $2\text{Na} + 2\text{H}_2\text{O}
ightarrow 2\text{NaOH} + \text{H}_2$
- $\text{Fe} + \text{Pb(NO}_3\text{)}_2
ightarrow \text{Fe(NO}_3\text{)}_2 + \text{Pb}$
- $\text{Cu} + \text{H}_2\text{O}
ightarrow \text{NR}$
- $\text{Cu} + \text{Al}_2(\text{SO}_4)_3
ightarrow \text{NR}$
- $2\text{Al} + 3\text{Pb(NO}_3\text{)}_2
ightarrow 2\text{Al(NO}_3\text{)}_3 + 3\text{Pb}$
- $\text{Cl}_2 + 2\text{NaI}
ightarrow 2\text{NaCl} + \text{I}_2$
- $\text{Fe} + 2\text{AgCH}_3\text{COO}
ightarrow \text{Fe(CH}_3\text{COO)}_2 + 2\text{Ag}$
- $2\text{Al} + 3\text{CuCl}_2
ightarrow 2\text{AlCl}_3 + 3\text{Cu}$
- $\text{Br}_2 + \text{CaI}_2
ightarrow \text{CaBr}_2 + \text{I}_2$
- $2\text{Al} + 6\text{HCl}
ightarrow 2\text{AlCl}_3 + 3\text{H}_2$
- $\text{Mg} + 2\text{HCl}
ightarrow \text{MgCl}_2 + \text{H}_2$
- $\text{Zn} + \text{H}_2\text{SO}_4
ightarrow \text{ZnSO}_4 + \text{H}_2$
- $\text{Fe} + \text{CuSO}_4
ightarrow \text{FeSO}_4 + \text{Cu}$
- $\text{Cl}_2 + \text{MgI}_2
ightarrow \text{MgCl}_2 + \text{I}_2$