Question

1. choose the the answer.

use gay-lussacs law to solve for the final pressure.
$p_1 = 2.50$ atm
$t_1 = 25.0 \\ ^\circ c$
$p_2 = ?$
$t_2 = 95.0 \\ ^\circ c$
0.658 atm
2.02 atm
3.09 atm

Explanation:

Step1: Convert temps to Kelvin

$T_1 = 25.0 + 273.15 = 298.15\ \text{K}$
$T_2 = 95.0 + 273.15 = 368.15\ \text{K}$

Step2: Apply Gay-Lussac's Law

Gay-Lussac's Law: $\frac{P_1}{T_1} = \frac{P_2}{T_2}$, rearranged to $P_2 = P_1 \times \frac{T_2}{T_1}$

Step3: Substitute values

$P_2 = 2.50\ \text{atm} \times \frac{368.15\ \text{K}}{298.15\ \text{K}}$

Step4: Calculate final pressure

$P_2 = 2.50 \times 1.2348 = 3.09\ \text{atm}$

Answer:

3.09 atm