Question

consider the half reaction below.
cu²⁺(aq) + 2e⁻ ⟶ cu(s)
which statement best describes what is taking place?
○ copper is being oxidized.
○ copper is being reduced.
○ copper is losing electrons.
○ copper is a reducing agent.

Explanation:

1. Recall the definitions: Oxidation is loss of electrons, reduction is gain of electrons. A reducing agent donates electrons (gets oxidized), an oxidizing agent accepts electrons (gets reduced).
2. Analyze the half - reaction $\ce{Cu^{2+}(aq) + 2e^- \longrightarrow Cu(s)}$: The copper ion ($\ce{Cu^{2+}}$) is gaining 2 electrons to form solid copper ($\ce{Cu}$).
3. Evaluate each option:

• "Copper is being oxidized": Oxidation is loss of electrons, but here $\ce{Cu^{2+}}$ is gaining electrons, so this is wrong.
• "Copper is being reduced": Since $\ce{Cu^{2+}}$ is gaining electrons (reduction is gain of electrons), this is correct.
• "Copper is losing electrons": In the reaction, $\ce{Cu^{2+}}$ is gaining electrons, not losing, so this is wrong.
• "Copper is a reducing agent": A reducing agent is oxidized (loses electrons), but here copper (in the form of $\ce{Cu^{2+}}$) is reduced (gains electrons), so it is an oxidizing agent, not a reducing agent.

Answer:

B. Copper is being reduced.