QUESTION IMAGE
Question
- dc and ac || de
mid - segments are || to the non - included side of the
ab is a transversal cutting df and bc
definition of transversal line
ab is a transversal cutting ac and de
m∠fad = m∠edb
m∠adf = m∠dbe
corresponding angles theorem
- ad = bd
definition of mid - point
- △dbe ≅ △adf
asa
- af=\frac{1}{2}ac
definition of mid - point
- de=\frac{1}{2}ac
transitive property of equality
what is the missing step in this proof? scroll down to see the entire proof.
a. statement: de=\frac{1}{2}af
reason: definition of mid - point
b. statement: de = af
reason: definition of mid - point
c. statement: de is parallel to ac
reason: definition of parallel lines
d. statement: de = af
reason: corresponding sides of congruent triangles are congruent
Explicación:
Paso 1: Analizar los pasos dados
Se han demostrado que $\triangle DBE\cong\triangle ADF$ por el criterio ASA.
Paso 2: Recordar propiedades de triángulos congruentes
Las partes correspondientes de triángulos congruentes son congruentes.
Respuesta:
D. Enunciado: $DE = AF$. Razonamiento: Las partes correspondientes de triángulos congruentes son congruentes.
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Explicación:
Paso 1: Analizar los pasos dados
Se han demostrado que $\triangle DBE\cong\triangle ADF$ por el criterio ASA.
Paso 2: Recordar propiedades de triángulos congruentes
Las partes correspondientes de triángulos congruentes son congruentes.
Respuesta:
D. Enunciado: $DE = AF$. Razonamiento: Las partes correspondientes de triángulos congruentes son congruentes.