Question

the density of a mystery metal is 455 noup/nollag. what is the density of the metal in g/ml? (remember... 1 ml = 1 cm³)

et units

et-metric relations

| length | 1 elim = 4500 toofs
1 dray = 5 toofs
1 toof = 15 chins | 1 chin = 5.00 cm |

mass	1 noup = 12 zones	1 noup = 255 g
volume	1 nollag = 2 halfs = 4 stips	1 nollag = 4.50 l

Explanation:

Step1: Convert noup to grams

We know that \( 1 \text{ noup} = 255 \text{ g} \), so for 455 noup, the mass in grams is \( 455 \times 255 \text{ g} \).
\( 455\times255 = 116025 \text{ g} \)

Step2: Convert nollag to liters then to milliliters

We know that \( 1 \text{ nollag} = 4.50 \text{ L} \), and since \( 1 \text{ L} = 1000 \text{ mL} \), we first convert nollag to liters and then to milliliters.
For 1 nollag, volume in liters is \( 4.50 \text{ L} \), so volume in milliliters is \( 4.50\times1000 = 4500 \text{ mL} \)

Step3: Calculate density in g/mL

Density is mass divided by volume, so we use the formula \( \text{Density} = \frac{\text{Mass}}{\text{Volume}} \)
Substituting the values we found: \( \text{Density} = \frac{116025 \text{ g}}{4500 \text{ mL}} \)
\( \frac{116025}{4500}=25.783\cdots\approx25.8 \text{ g/mL} \) (rounded to three significant figures)

Answer:

\( \approx 25.8 \text{ g/mL} \)