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Question
9 the diagram below shows the lewis dot structure for different elements. the electron configuration for an unknown element is 1s²2s²2p³. which of the following represents its lewis dot structure? 1. b 2. c 3. n 4. f clear all 4 3 2 1
Step1: Determine the number of valence - electrons
The electron configuration of the unknown element is \(1s^{2}2s^{2}2p^{3}\). The valence - shell electrons are in the \(n = 2\) shell. The number of electrons in the \(2s\) and \(2p\) orbitals is \(2 + 3=5\).
Step2: Analyze the Lewis - dot structures
In a Lewis - dot structure, the number of dots around the symbol of an element represents the number of valence electrons.
- For structure 1 (Boron), it has 3 valence electrons.
- For structure 2 (Carbon), it has 4 valence electrons.
- For structure 3 (Nitrogen), it has 5 valence electrons.
- For structure 4 (Fluorine), it has 7 valence electrons.
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