QUESTION IMAGE
Question
directions: solve the following equations. be sure to use the correct number of decimal places in your answer.
- 3.9121 g + 70.51 g =
before rounding:
after rounding:
- 0.085 cm + 0.062 cm + 0.14 cm =
before rounding:
after rounding:
- 50.012 ml + 61.2312 ml =
before rounding:
after rounding:
- 120 kg - 25.00 kg =
Step1: Calculate 1.
Add the two values: $3.9121\ g+70.51\ g = 74.4221\ g$. Since the least number of decimal - places in the values being added is 2 (in 70.51), we round to 2 decimal places. So, it becomes $74.42\ g$.
Step2: Calculate 2.
Add the lengths: $0.085\ cm + 0.062\ cm+0.14\ cm=0.287\ cm$. The least number of decimal - places in the values being added is 2 (in 0.14), so we round to 2 decimal places. It becomes $0.29\ cm$.
Step3: Calculate 3.
Add the volumes: $50.012\ ml+61.2312\ ml = 111.2432\ ml$. The least number of decimal - places in the values being added is 3 (in 50.012), so we round to 3 decimal places. It becomes $111.243\ ml$.
Step4: Calculate 5.
Subtract the masses: $120\ kg - 25.00\ kg=95.00\ kg$. The least number of decimal - places in the values being subtracted is 2 (in 25.00), so the result is $95.00\ kg$.
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- Before Rounding: $74.4221\ g$, After Rounding: $74.42\ g$
- Before Rounding: $0.287\ cm$, After Rounding: $0.29\ cm$
- Before Rounding: $111.2432\ ml$, After Rounding: $111.243\ ml$
- Before Rounding: $95.00\ kg$, After Rounding: $95.00\ kg$