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directions: solve the following equations. be sure to use the correct n…

Question

directions: solve the following equations. be sure to use the correct number of decimal places in your answer.

  1. 3.9121 g + 70.51 g =

before rounding:
after rounding:

  1. 0.085 cm + 0.062 cm + 0.14 cm =

before rounding:
after rounding:

  1. 50.012 ml + 61.2312 ml =

before rounding:
after rounding:

  1. 120 kg - 25.00 kg =

Explanation:

Step1: Calculate 1.

Add the two values: $3.9121\ g+70.51\ g = 74.4221\ g$. Since the least number of decimal - places in the values being added is 2 (in 70.51), we round to 2 decimal places. So, it becomes $74.42\ g$.

Step2: Calculate 2.

Add the lengths: $0.085\ cm + 0.062\ cm+0.14\ cm=0.287\ cm$. The least number of decimal - places in the values being added is 2 (in 0.14), so we round to 2 decimal places. It becomes $0.29\ cm$.

Step3: Calculate 3.

Add the volumes: $50.012\ ml+61.2312\ ml = 111.2432\ ml$. The least number of decimal - places in the values being added is 3 (in 50.012), so we round to 3 decimal places. It becomes $111.243\ ml$.

Step4: Calculate 5.

Subtract the masses: $120\ kg - 25.00\ kg=95.00\ kg$. The least number of decimal - places in the values being subtracted is 2 (in 25.00), so the result is $95.00\ kg$.

Answer:

  1. Before Rounding: $74.4221\ g$, After Rounding: $74.42\ g$
  2. Before Rounding: $0.287\ cm$, After Rounding: $0.29\ cm$
  3. Before Rounding: $111.2432\ ml$, After Rounding: $111.243\ ml$
  4. Before Rounding: $95.00\ kg$, After Rounding: $95.00\ kg$