Question

for each of the following draw structural formula of parent acid and parent alcohol
ch₃-ch₂-\stackrel{o}{\stackrel{||}{c}}-o-ch₂-ch₃

Explanation:

To determine the parent acid and parent alcohol of the given ester, we analyze the ester structure:

Step 1: Identify the ester functional group

The given compound is an ester, with the general formula \( \text{R-COO-R'} \), where the ester linkage is \( -\text{COO}- \). In the structure \( \text{CH}_3-\text{CH}_2-\text{C}(\text{O})-\text{O}-\text{CH}_2-\text{CH}_3 \) (corrected for clarity: \( \text{CH}_3\text{CH}_2\text{COOCH}_2\text{CH}_3 \)):

• The part before the \( -\text{COO}- \) group (the acyl group) comes from the parent acid.
• The part after the \( -\text{O}- \) (attached to the alkyl group) comes from the parent alcohol.

Step 2: Deduce the parent acid

The acyl group (before \( -\text{COO}- \)) is \( \text{CH}_3\text{CH}_2\text{CO}- \) (propionyl group). To find the parent acid, we replace \( -\text{O-R'} \) with \( -\text{OH} \). Thus, the parent acid is \( \text{CH}_3\text{CH}_2\text{COOH} \) (propanoic acid).

Step 3: Deduce the parent alcohol

The alkyl group after \( -\text{O}- \) is \( \text{CH}_3\text{CH}_2- \) (ethyl group). To find the parent alcohol, we replace the acyl group (\( \text{CH}_3\text{CH}_2\text{CO}- \)) with \( -\text{H} \) (and keep the \( -\text{OH} \) from the alcohol). Thus, the parent alcohol is \( \text{CH}_3\text{CH}_2\text{OH} \) (ethanol).

Structural Formulas:

• Parent Acid (Propanoic Acid):

\( \text{CH}_3-\text{CH}_2-\text{C}(\text{O})-\text{OH} \) (or expanded: \( \text{H}_3\text{C}-\text{CH}_2-\text{COOH} \))

• Parent Alcohol (Ethanol):

\( \text{CH}_3-\text{CH}_2-\text{OH} \) (or expanded: \( \text{H}_3\text{C}-\text{CH}_2-\text{OH} \))

Final Answer:

• Parent Acid: Propanoic Acid (\( \boldsymbol{\text{CH}_3\text{CH}_2\text{COOH}} \))
• Parent Alcohol: Ethanol (\( \boldsymbol{\text{CH}_3\text{CH}_2\text{OH}} \))

Answer:

To determine the parent acid and parent alcohol of the given ester, we analyze the ester structure:

Step 1: Identify the ester functional group

The given compound is an ester, with the general formula \( \text{R-COO-R'} \), where the ester linkage is \( -\text{COO}- \). In the structure \( \text{CH}_3-\text{CH}_2-\text{C}(\text{O})-\text{O}-\text{CH}_2-\text{CH}_3 \) (corrected for clarity: \( \text{CH}_3\text{CH}_2\text{COOCH}_2\text{CH}_3 \)):

• The part before the \( -\text{COO}- \) group (the acyl group) comes from the parent acid.
• The part after the \( -\text{O}- \) (attached to the alkyl group) comes from the parent alcohol.

Step 2: Deduce the parent acid

The acyl group (before \( -\text{COO}- \)) is \( \text{CH}_3\text{CH}_2\text{CO}- \) (propionyl group). To find the parent acid, we replace \( -\text{O-R'} \) with \( -\text{OH} \). Thus, the parent acid is \( \text{CH}_3\text{CH}_2\text{COOH} \) (propanoic acid).

Step 3: Deduce the parent alcohol

The alkyl group after \( -\text{O}- \) is \( \text{CH}_3\text{CH}_2- \) (ethyl group). To find the parent alcohol, we replace the acyl group (\( \text{CH}_3\text{CH}_2\text{CO}- \)) with \( -\text{H} \) (and keep the \( -\text{OH} \) from the alcohol). Thus, the parent alcohol is \( \text{CH}_3\text{CH}_2\text{OH} \) (ethanol).

Structural Formulas:

• Parent Acid (Propanoic Acid):

\( \text{CH}_3-\text{CH}_2-\text{C}(\text{O})-\text{OH} \) (or expanded: \( \text{H}_3\text{C}-\text{CH}_2-\text{COOH} \))

• Parent Alcohol (Ethanol):

\( \text{CH}_3-\text{CH}_2-\text{OH} \) (or expanded: \( \text{H}_3\text{C}-\text{CH}_2-\text{OH} \))

Final Answer:

• Parent Acid: Propanoic Acid (\( \boldsymbol{\text{CH}_3\text{CH}_2\text{COOH}} \))
• Parent Alcohol: Ethanol (\( \boldsymbol{\text{CH}_3\text{CH}_2\text{OH}} \))