Question

1. element x has 3 isotopes. one isotope has a mass of 127.0 and is found in 80% abundance. another isotope has a mass of 126.0 and is found in 17% abundance. the final isotope has a mass of 128.0 and is found in 3% abundance. show work to calculate the average atomic mass of this atom:

Explanation:

Step1: Convert abundances to decimals

$80\% = 0.8$, $17\%=0.17$, $3\% = 0.03$

Step2: Multiply mass by abundance for each isotope

For first isotope: $127.0\times0.8 = 101.6$
For second isotope: $126.0\times0.17=21.42$
For third isotope: $128.0\times0.03 = 3.84$

Step3: Sum up the products

$101.6+21.42 + 3.84=126.86$

Answer:

$126.86$