Question

if the empirical formula is ch and the molar mass is 78 g/mol, what is the molecular formula?
12.01 h.008
13.018
$\frac{78}{13.018}=6$
6(ch)
$c_6h_6$
metry unit
its not rocket science 2023
20

Explanation:

Step1: Calculate empirical formula mass

$\text{Empirical formula mass} = 12.01\ \text{g/mol} + 1.008\ \text{g/mol} = 13.018\ \text{g/mol}$

Step2: Find the scaling factor $n$

$n = \frac{\text{Molar mass}}{\text{Empirical formula mass}} = \frac{78\ \text{g/mol}}{13.018\ \text{g/mol}} \approx 6$

Step3: Multiply empirical formula by $n$

$\text{Molecular formula} = n \times (\text{CH}) = 6\times(\text{CH})$

Answer:

$\text{C}_6\text{H}_6$