Question

1. estimate the volume occupied by 23.9 mol of nitrogen at satp conditions

□ 542l
□ 1.69×10⁻³l
□ 1.84×10⁻³l
□ 592l

Explanation:

Step1: Recall molar - volume at SATP

At SATP (Standard Ambient Temperature and Pressure: 25°C or 298 K and 100 kPa), the molar volume of an ideal gas is approximately 24.8 L/mol.

Step2: Calculate the volume of nitrogen

We use the formula $V = n\times V_m$, where $n$ is the number of moles and $V_m$ is the molar volume. Given $n = 23.9$ mol and $V_m=24.8$ L/mol.
$V=23.9\times24.8$
$V = 23.9\times(25 - 0.2)$
$V=23.9\times25-23.9\times0.2$
$V = 597.5-4.78$
$V\approx592$ L

Answer:

592L