Question

examine the chemical equations as being balanced or not balanced. co + hno = hco₂ + h₂ 6co₂ + 6h₂o = c₆h₁₂o₆ + o₂ h₂co₃ = h₂o + co₂ 4cu + o₂ = cuo balanced not balanced

Explanation:

Step1: Analyze first equation

$CO + NO=CO_2 + N_2$ has 1 C on left, 1 C on right; 1 O on left (in CO), 2 O on right (in $CO_2$); 1 N on left, 2 N on right. Not balanced.

Step2: Analyze second equation

$CO_2+H_2O = C_6H_{12}O_6+O_2$ has 1 C on left, 6 C on right; 3 O on left, 8 O on right (in $C_6H_{12}O_6$ and $O_2$); 2 H on left, 12 H on right. Not balanced.

Step3: Analyze third equation

$H_2CO_3 = H_2O+CO_2$ has 1 C on left, 1 C on right; 3 O on left, 3 O on right; 2 H on left, 2 H on right. Balanced.

Step4: Analyze fourth equation

$Cu + O_2=CuO$ has 1 Cu on left, 1 Cu on right; 2 O on left, 1 O on right. Not balanced.

Answer:

Balanced: $H_2CO_3 = H_2O+CO_2$
Not Balanced: $CO + NO=CO_2 + N_2$, $CO_2+H_2O = C_6H_{12}O_6+O_2$, $Cu + O_2=CuO$