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Question
factor completely.
$3d^2 - 66d - 69$
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Step1: Factor out GCF
$3d^2 - 66d - 69 = 3(d^2 - 22d - 23)$
Step2: Factor quadratic trinomial
Find two numbers: $-23$ and $1$, since $-23 \times 1 = -23$ and $-23 + 1 = -22$.
$d^2 - 22d - 23 = (d - 23)(d + 1)$
Step3: Combine factors
Substitute back into the expression.
$3(d - 23)(d + 1)$
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$3(d - 23)(d + 1)$