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factor completely. $3d^2 - 66d - 69$ save answer

Question

factor completely.
$3d^2 - 66d - 69$
save answer

Explanation:

Step1: Factor out GCF

$3d^2 - 66d - 69 = 3(d^2 - 22d - 23)$

Step2: Factor quadratic trinomial

Find two numbers: $-23$ and $1$, since $-23 \times 1 = -23$ and $-23 + 1 = -22$.
$d^2 - 22d - 23 = (d - 23)(d + 1)$

Step3: Combine factors

Substitute back into the expression.
$3(d - 23)(d + 1)$

Answer:

$3(d - 23)(d + 1)$