Question

fill in the blank question
a box being pushed by a force results in an acceleration of $2\\ \text{m/s}^2$. the force is then halved, resulting in an acceleration of $\text{m/s}^2$.

Explanation:

Step1: Recall Newton's second law

$F = ma$

Step2: Isolate initial acceleration

$a_1 = \frac{F_1}{m} = 2\ \text{m/s}^2$

Step3: Define new force

$F_2 = \frac{F_1}{2}$

Step4: Calculate new acceleration

$a_2 = \frac{F_2}{m} = \frac{\frac{F_1}{2}}{m} = \frac{1}{2} \times \frac{F_1}{m} = \frac{1}{2}a_1$
$a_2 = \frac{1}{2} \times 2\ \text{m/s}^2 = 1\ \text{m/s}^2$

Answer:

$1$