Question

fill in the information missing from this table.
nuclide | protons | neutrons | z | a
--- | --- | --- | --- | ---

		34	78
19	20

$\ce{^{13}_{6}c}$ | | | |

Explanation:

Step1: Recall definitions

• \( Z \) (atomic number) = number of protons.
• \( A \) (mass number) = number of protons + number of neutrons.
• Nuclide symbol: \( _Z^A X \), where \( X \) is the element symbol (determined by \( Z \) from periodic table).

Step2: First row (Z=34, A=78)

• Protons = \( Z = 34 \).
• Neutrons = \( A - Z = 78 - 34 = 44 \).
• Element with \( Z = 34 \) is Selenium (Se), so nuclide: \( _{34}^{78}\text{Se} \).

Step3: Second row (protons=19, neutrons=20)

• \( Z = \) protons \( = 19 \) (element: Potassium, K).
• \( A = \) protons + neutrons \( = 19 + 20 = 39 \).
• Nuclide: \( _{19}^{39}\text{K} \).

Step4: Third row (\( _{6}^{13}\text{C} \))

• Protons = \( Z = 6 \) (since \( Z = 6 \) for Carbon).
• Neutrons = \( A - Z = 13 - 6 = 7 \).
• \( Z = 6 \), \( A = 13 \).

Filled Table:

nuclide	protons	neutrons	\( Z \)	\( A \)
\( _{19}^{39}\text{K} \)	19	20	19	39
\( _{6}^{13}\text{C} \)	6	7	6	13

(For the answer, presenting the filled values as per each cell's requirement:)

First row:

• Nuclide: \( \boldsymbol{_{34}^{78}\text{Se}} \)
• Protons: \( \boldsymbol{34} \)
• Neutrons: \( \boldsymbol{44} \)

Second row:

• Nuclide: \( \boldsymbol{_{19}^{39}\text{K}} \)
• \( Z \): \( \boldsymbol{19} \)
• \( A \): \( \boldsymbol{39} \)

Third row:

• Protons: \( \boldsymbol{6} \)
• Neutrons: \( \boldsymbol{7} \)
• \( Z \): \( \boldsymbol{6} \)
• \( A \): \( \boldsymbol{13} \)

Answer:

Step1: Recall definitions

• \( Z \) (atomic number) = number of protons.
• \( A \) (mass number) = number of protons + number of neutrons.
• Nuclide symbol: \( _Z^A X \), where \( X \) is the element symbol (determined by \( Z \) from periodic table).

Step2: First row (Z=34, A=78)

• Protons = \( Z = 34 \).
• Neutrons = \( A - Z = 78 - 34 = 44 \).
• Element with \( Z = 34 \) is Selenium (Se), so nuclide: \( _{34}^{78}\text{Se} \).

Step3: Second row (protons=19, neutrons=20)

• \( Z = \) protons \( = 19 \) (element: Potassium, K).
• \( A = \) protons + neutrons \( = 19 + 20 = 39 \).
• Nuclide: \( _{19}^{39}\text{K} \).

Step4: Third row (\( _{6}^{13}\text{C} \))

• Protons = \( Z = 6 \) (since \( Z = 6 \) for Carbon).
• Neutrons = \( A - Z = 13 - 6 = 7 \).
• \( Z = 6 \), \( A = 13 \).

Filled Table:

nuclide	protons	neutrons	\( Z \)	\( A \)
\( _{19}^{39}\text{K} \)	19	20	19	39
\( _{6}^{13}\text{C} \)	6	7	6	13

(For the answer, presenting the filled values as per each cell's requirement:)

First row:

• Nuclide: \( \boldsymbol{_{34}^{78}\text{Se}} \)
• Protons: \( \boldsymbol{34} \)
• Neutrons: \( \boldsymbol{44} \)

Second row:

• Nuclide: \( \boldsymbol{_{19}^{39}\text{K}} \)
• \( Z \): \( \boldsymbol{19} \)
• \( A \): \( \boldsymbol{39} \)

Third row:

• Protons: \( \boldsymbol{6} \)
• Neutrons: \( \boldsymbol{7} \)
• \( Z \): \( \boldsymbol{6} \)
• \( A \): \( \boldsymbol{13} \)