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Question
fill in the missing information:
| symbol | atom or ion? (check all that apply) | number of protons | number of electrons |
|---|---|---|---|
| ru | ☐ neutral atom ☐ cation ☐ anion | ☐ | ☐ |
| ☐ | ☐ neutral atom ☐ cation ☐ anion | 9 | 10 |
For $\boldsymbol{\ce{Mg^{2+}}}$:
Step1: Determine atom/ion type
$\ce{Mg^{2+}}$ has a positive charge, so it's a cation (not neutral atom or anion).
Step2: Find number of protons
Magnesium (Mg) has an atomic number of 12, so protons = 12.
Step3: Find number of electrons
For a cation with $2+$ charge, electrons = protons - charge = $12 - 2 = 10$.
Step1: Determine atom/ion type
$\ce{Ru}$ (Ruthenium) has no charge, so it's a neutral atom (not cation or anion).
Step2: Find number of protons
Ruthenium has an atomic number of 44, so protons = 44.
Step3: Find number of electrons
In a neutral atom, electrons = protons = 44.
Step1: Determine atom/ion type
Electrons (10) > protons (9), so it's an anion (negative charge, not neutral atom or cation).
Step2: Identify the element
Atomic number = protons = 9, which is fluorine (F). The ion is $\ce{F^-}$ (since electrons = protons + 1, charge = $-1$).
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(for $\ce{Mg^{2+}}$):
- atom or ion: cation (check cation box)
- number of protons: 12
- number of electrons: 10