Question

fill in the missing words
if the following reaction is balanced correctly
$al + hno_3
ightarrow al(no_3)_3 + h_2$, the coefficient in front of $h_2$ is
, and the coefficient in front of al is
.

Explanation:

Step1: Balance nitrogen atoms

To balance the nitrogen atoms in $HNO_3$ and $Al(NO_3)_3$, we need 6 moles of $HNO_3$ for every 2 moles of $Al(NO_3)_3$. So the un - balanced equation becomes $Al + 6HNO_3
ightarrow2Al(NO_3)_3 + H_2$.

Step2: Balance aluminum atoms

To balance aluminum atoms, we need 2 moles of $Al$. The equation is $2Al+6HNO_3
ightarrow2Al(NO_3)_3 + H_2$.

Step3: Balance hydrogen atoms

On the left - hand side, we have 6 moles of hydrogen from $6HNO_3$. On the right - hand side, to balance hydrogen, we need 3 moles of $H_2$. The balanced equation is $2Al + 6HNO_3=2Al(NO_3)_3+3H_2$.

Answer:

The coefficient in front of $H_2$ is 3, and the coefficient in front of $Al$ is 2.