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5) find the measure of angle bdc. 6) find the measure of angle a. 7) fi…

Question

  1. find the measure of angle bdc.
  2. find the measure of angle a.
  3. find the value of x.
  4. find the missing angle.

Explanation:

Response
Problem 5: Find the measure of angle BDC

Step 1: Use the exterior angle theorem

The exterior angle theorem states that an exterior angle of a triangle is equal to the sum of the two non - adjacent interior angles. In triangle \(BDC\), \(\angle VBC\) is an exterior angle, so \(20x + 5=(9x - 2)+40\)

Step 2: Solve for \(x\)

\[

$$\begin{align*} 20x+5&=9x - 2+40\\ 20x+5&=9x + 38\\ 20x-9x&=38 - 5\\ 11x&=33\\ x&=3 \end{align*}$$

\]

Step 3: Find the measure of \(\angle BDC\)

Substitute \(x = 3\) into the expression for \(\angle BDC\) which is \(9x-2\)
\(\angle BDC=9\times3 - 2=27 - 2 = 25^{\circ}\)

Step 1: Use the angle sum property of a right - triangle

In a right - triangle, the sum of the two non - right angles is \(90^{\circ}\). So \((x + 37)+(x + 67)=90\)

Step 2: Solve for \(x\)

\[

$$\begin{align*} x+37+x + 67&=90\\ 2x+104&=90\\ 2x&=90 - 104\\ 2x&=- 14\\ x&=-7 \end{align*}$$

\]

Step 3: Find the measure of \(\angle A\)

Substitute \(x=-7\) into the expression for \(\angle A\) which is \(x + 37\)
\(\angle A=-7 + 37=30^{\circ}\)

Step 1: Use the angle sum property of a triangle

The sum of the interior angles of a triangle is \(180^{\circ}\). So \((x + 8)+(2x-3)+(6x - 5)=180\)

Step 2: Solve for \(x\)

\[

$$\begin{align*} x + 8+2x-3+6x - 5&=180\\ ( x+2x + 6x)+(8-3 - 5)&=180\\ 9x+0&=180\\ x&=20 \end{align*}$$

\]

Answer:

\(25^{\circ}\)

Problem 6: Find the measure of angle A