QUESTION IMAGE
Question
- find the measure of angle bdc.
- find the measure of angle a.
- find the value of x.
- find the missing angle.
Problem 5: Find the measure of angle BDC
Step 1: Use the exterior angle theorem
The exterior angle theorem states that an exterior angle of a triangle is equal to the sum of the two non - adjacent interior angles. In triangle \(BDC\), \(\angle VBC\) is an exterior angle, so \(20x + 5=(9x - 2)+40\)
Step 2: Solve for \(x\)
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Step 3: Find the measure of \(\angle BDC\)
Substitute \(x = 3\) into the expression for \(\angle BDC\) which is \(9x-2\)
\(\angle BDC=9\times3 - 2=27 - 2 = 25^{\circ}\)
Step 1: Use the angle sum property of a right - triangle
In a right - triangle, the sum of the two non - right angles is \(90^{\circ}\). So \((x + 37)+(x + 67)=90\)
Step 2: Solve for \(x\)
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Step 3: Find the measure of \(\angle A\)
Substitute \(x=-7\) into the expression for \(\angle A\) which is \(x + 37\)
\(\angle A=-7 + 37=30^{\circ}\)
Step 1: Use the angle sum property of a triangle
The sum of the interior angles of a triangle is \(180^{\circ}\). So \((x + 8)+(2x-3)+(6x - 5)=180\)
Step 2: Solve for \(x\)
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\(25^{\circ}\)