Question

gaseous ammonia chemically reacts with oxygen (o₂) gas to produce nitrogen monoxide gas and water vapor. calculate the moles of water produced by the reaction of 1.8 mol of ammonia. be sure your answer has a unit symbol, if necessary, and round it to the correct number of significant digits.

Explanation:

Step1: Write the balanced chemical equation

$4NH_3 + 5O_2
ightarrow4NO + 6H_2O$

Step2: Determine the mole - ratio

From the balanced equation, the mole - ratio of $NH_3$ to $H_2O$ is $4:6$ or $\frac{2}{3}$.

Step3: Calculate moles of water

Let $n_{H_2O}$ be the moles of water and $n_{NH_3}=1.8$ mol. Using the mole - ratio $\frac{n_{H_2O}}{n_{NH_3}}=\frac{6}{4}$, we have $n_{H_2O}=\frac{6}{4}\times n_{NH_3}$. Substitute $n_{NH_3} = 1.8$ mol into the equation: $n_{H_2O}=\frac{6}{4}\times1.8$ mol$ = 2.7$ mol.

Answer:

$2.7$ mol