Question

1. a generator converts 103,200,000 j of chemical energy into 40,932,200 j of electrical energy. how efficient is the generator? round to the nearest percent. 40% 41% 38% 39%

Explanation:

Step1: Recall efficiency formula

Efficiency = $\frac{\text{Useful Output Energy}}{\text{Total Input Energy}} \times 100\%$

Step2: Plug in given values

Input energy = $103,200,000$ J, Output energy = $40,932,200$ J
Expression: $\text{Efficiency} = \frac{40,932,200}{103,200,000} \times 100\%$

Step3: Calculate the ratio

$\frac{40,932,200}{103,200,000} \approx 0.3966$

Step4: Convert to percent and round

$0.3966 \times 100\% \approx 39\%$

Answer:

D. 39%