Question

a graduated cylinder contains 15.75 ml of water. a metal that weighs 2.5000e1 g is added. the final volume reading is 38.55 ml. 1. determine volume of metal: report result to the same number of decimal places as the number with the least number of decimal places. use this volume in calculation. 2. determine density of metal: d = m/v report result to the same number of significant figures as the number with the least number of significant figures. do not use exponential notation in answer. do not include unit, g/ml. respond with the correct number of significant figures in scientific notation (use e notation and only 1 digit before decimal e.g. 2.5e5 for 2.5×10^5) type your numeric answer and submit

Explanation:

Step1: Calculate volume of metal

The volume of the metal is the final volume of water - initial volume of water. So $V = 38.55 - 15.75=22.8$ mL.

Step2: Calculate density of metal

The mass of the metal $M = 2.5000E1$ g which is $25.000$ g. Using the density formula $D=\frac{M}{V}$, we substitute $M = 25.000$ g and $V = 22.8$ mL. So $D=\frac{25.000}{22.8}\approx1.09649$. The mass has 5 significant - figures and the volume has 3 significant - figures. Rounding to 3 significant - figures, $D = 1.10$.

Answer:

$1.10$