Question

a graduated cylinder contains 21.0 ml of water. when you place a gold ring in the water, the graduated cylinder reading is 23.5 ml. you place the same gold ring in a different graduated cylinder that contains 37.5 ml of water. what do you expect the reading of this graduated cylinder to be? graduated cylinder reading:

Explanation:

Step1: Calculate ring's volume

The volume of the gold - ring is found by the change in volume in the first graduated cylinder. The initial volume of water is $V_1 = 21.0$ mL and the final volume is $V_2=23.5$ mL. So the volume of the ring $V = V_2 - V_1$.
$V=23.5 - 21.0=2.5$ mL

Step2: Find new graduated - cylinder reading

When the ring is placed in the second graduated cylinder with an initial volume of water $V_{i}=37.5$ mL, the final volume $V_{f}$ is the sum of the initial volume of water and the volume of the ring.
$V_{f}=37.5 + 2.5$
$V_{f}=40.0$ mL

Answer:

40.0 mL