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graphing linear equations vectored instruction graph the equation by fi…

Question

graphing linear equations vectored instruction graph the equation by filling in the chart. equation: y = 3x+1

Explanation:

Step1: Substitute x = 2 into the equation

We have the equation \( y = 3x + 1 \). Substitute \( x = 2 \) into it.
\( y = 3\times2 + 1 \)

Step2: Calculate the value of y

First, calculate \( 3\times2 = 6 \), then add 1: \( 6 + 1 = 7 \).
\( y = 7 \)

Step3: Substitute x = 3 into the equation

Substitute \( x = 3 \) into \( y = 3x + 1 \).
\( y = 3\times3 + 1 \)

Step4: Calculate the value of y for x = 3

Calculate \( 3\times3 = 9 \), then add 1: \( 9 + 1 = 10 \).
\( y = 10 \)

Step5: Substitute x = 4 into the equation

Substitute \( x = 4 \) into \( y = 3x + 1 \).
\( y = 3\times4 + 1 \)

Step6: Calculate the value of y for x = 4

Calculate \( 3\times4 = 12 \), then add 1: \( 12 + 1 = 13 \).
\( y = 13 \)

Answer:

For \( x = 2 \), \( y = 7 \); for \( x = 3 \), \( y = 10 \); for \( x = 4 \), \( y = 13 \)

So the completed table is:

XY
14
27
310
413