Question

heres the dimensional analysis setup from the previous problem:
$14.3 \frac{moles\\ h_2o}{1} \times \frac{1moleo_2}{2molesh_2o} =$

Explanation:

Step1: Cancel matching units

The units of moles $\text{H}_2\text{O}$ cancel out.
$14.3 \ \cancel{\text{moles H}_2\text{O}} \times \frac{1\text{ mole O}_2}{2\cancel{\text{moles H}_2\text{O}}}$

Step2: Calculate the result

Divide 14.3 by 2 to find moles of $\text{O}_2$.
$\frac{14.3}{2} = 7.15$

Answer:

7.15 moles of $\text{O}_2$