Question

1. how many milliliters of the approximately 0.11 m prepared copper(ii) sulfate stock solution are needed to prepare 100.00 milliliters of a 0.011 m copper(ii) sulfate solution? ml

Explanation:

Step1: Use dilution formula

$M_1V_1 = M_2V_2$

Step2: Identify values

$M_1 = 0.11\ M$, $V_2=100.00\ mL$, $M_2 = 0.011\ M$

Step3: Solve for $V_1$

$V_1=\frac{M_2V_2}{M_1}=\frac{0.011\ M\times100.00\ mL}{0.11\ M}$
$V_1 = 10.00\ mL$

Answer:

$10.00$