Question

how many moles of caco₃ would contain 14.5 g of oxygen atoms? 1. 0.302 mol 2. 0.0716 mol 3. 2.72 mol 4. 696 mol 5. 8.03×10⁻²⁴ mol 6. 77.3 mol

Explanation:

Step 1: Calculate moles of O atoms

Molar mass of O is \(16.00\space g/mol\). Moles of O = \(\frac{mass\space of\space O}{molar\space mass\space of\space O}\) = \(\frac{14.5\space g}{16.00\space g/mol}\) ≈ \(0.90625\space mol\).

Step 2: Relate moles of O to moles of \(CaCO_3\)

In \(CaCO_3\), 1 mole of \(CaCO_3\) contains 3 moles of O. So, moles of \(CaCO_3\) = \(\frac{moles\space of\space O}{3}\) = \(\frac{0.90625\space mol}{3}\) ≈ \(0.0716\space mol\).

Answer:

1. 0.0716 mol