Question

3.) how many moles are there in 45.0 grams of sulfuric acid, h₂so₄? your answer should be rounded to three significant figures. (1 point) 98.1 moles 2.18 moles 0.459 moles 4.) what is the mass in grams of 0.700 moles of water, h₂o? your answer should be rounded to three significant figures. (1 point) 12.6 g 25.7 g 18.0 g

Explanation:

Step1: Calculate molar mass of $H_2SO_4$

The molar mass of $H = 1.01\ g/mol$, $S=32.07\ g/mol$, $O = 16.00\ g/mol$. For $H_2SO_4$, $M=(2\times1.01)+32.07+(4\times16.00)=98.09\ g/mol$.

Step2: Calculate moles of $H_2SO_4$

Use the formula $n=\frac{m}{M}$, where $m = 45.0\ g$ and $M = 98.09\ g/mol$. So $n=\frac{45.0}{98.09}\approx0.459\ mol$.

Step3: Calculate molar mass of $H_2O$

The molar mass of $H = 1.01\ g/mol$ and $O = 16.00\ g/mol$. For $H_2O$, $M=(2\times1.01)+16.00 = 18.02\ g/mol$.

Step4: Calculate mass of $H_2O$

Use the formula $m=n\times M$, where $n = 0.700\ mol$ and $M = 18.02\ g/mol$. So $m=0.700\times18.02 = 12.614\approx12.6\ g$.

Answer:

1. C. 0.459 moles
2. A. 12.6 g