Question

lead melts at 601.0°c. what temperature is this in °f?
302°f
365°f
1,050°f
1,082°f
1,114°f

Explanation:

Step1: Recall the formula to convert Celsius to Fahrenheit

The formula to convert temperature from Celsius ($^\circ$C) to Fahrenheit ($^\circ$F) is $^\circ\text{F} = \frac{9}{5} \times ^\circ\text{C} + 32$.

Step2: Substitute the given Celsius temperature into the formula

We are given that the temperature in Celsius is $601.0^\circ$C. Substitute $^\circ\text{C} = 601.0$ into the formula:
\[
^\circ\text{F} = \frac{9}{5} \times 601.0 + 32
\]

Step3: Calculate $\frac{9}{5} \times 601.0$

First, calculate $\frac{9}{5} \times 601.0$. $\frac{9}{5} = 1.8$, so $1.8 \times 601.0 = 1081.8$.

Step4: Add 32 to the result

Now, add 32 to 1081.8: $1081.8 + 32 = 1113.8 \approx 1114$.

Answer:

1,114°F (the option with "1,114°F")