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e and f are mutually exclusive events. p(e) = 0.15; p(f) = 0.71. find p…

Question

e and f are mutually exclusive events. p(e) = 0.15; p(f) = 0.71. find p(e | f)

Explanation:

Step1: Mutually exclusive events have P(E∩F)=0

Mutually exclusive events cannot co-occur, so \( P(E \cap F) = 0 \).

Step2: Apply conditional probability formula

\( P(E|F) = \frac{P(E \cap F)}{P(F)} = \frac{0}{0.71} = 0 \)

Answer:

0