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Question
e and f are mutually exclusive events. p(e) = 0.15; p(f) = 0.71. find p(e | f)
Step1: Mutually exclusive events have P(E∩F)=0
Mutually exclusive events cannot co-occur, so \( P(E \cap F) = 0 \).
Step2: Apply conditional probability formula
\( P(E|F) = \frac{P(E \cap F)}{P(F)} = \frac{0}{0.71} = 0 \)
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