Question

1. name each compound below: al3s2 au2o cacl2 naf name formula

Explanation:

Step1: Identify cation and anion for $Al_2S_3$

Aluminum ($Al$) is the cation with a +3 charge and sulfur ($S$) is the anion with a - 2 charge. The compound is named aluminum sulfide.

Step2: Identify cation and anion for $Au_2O$

Gold ($Au$) is the cation and oxygen ($O$) is the anion. Gold can have different oxidation - states. Here, since oxygen has a - 2 charge and there are 2 gold atoms, the oxidation state of gold is +1. The compound is named gold(I) oxide.

Step3: Identify cation and anion for $CaCl_2$

Calcium ($Ca$) is the cation with a +2 charge and chlorine ($Cl$) is the anion with a - 1 charge. The compound is named calcium chloride.

Step4: Identify cation and anion for $NaF$

Sodium ($Na$) is the cation with a +1 charge and fluorine ($F$) is the anion with a - 1 charge. The compound is named sodium fluoride.

Answer:

Aluminum sulfide
Gold(I) oxide
Calcium chloride
Sodium fluoride