Question

1. nh₃ + o₂ → n₂ + h₂o after correctly balancing this chemical equation, what coefficient will go before nh₃? enter the correct answer in the box.

Explanation:

Step1: Balance N atoms

Let the coefficient of \( \text{NH}_3 \) be \( x \), \( \text{N}_2 \) be \( y \). From N: \( x = 2y \). Let's start with \( x = 4 \), then \( y = 2 \) (to make N balanced: 4 N on left, 4 N on right as \( 2\times2 \)).

Step2: Balance H atoms

With \( x = 4 \) ( \( \text{NH}_3 \) ), H atoms: \( 4\times3 = 12 \). So \( \text{H}_2\text{O} \) coefficient: \( \frac{12}{2}=6 \) (since each \( \text{H}_2\text{O} \) has 2 H).

Step3: Balance O atoms

\( \text{H}_2\text{O} \) has 6 O, so \( \text{O}_2 \) coefficient: \( \frac{6}{2}=3 \) (each \( \text{O}_2 \) has 2 O).
Now check: \( 4\text{NH}_3 + 3\text{O}_2
ightarrow 2\text{N}_2 + 6\text{H}_2\text{O} \). All atoms balanced.

Answer:

4