Question

do now
name: madison c date: feb 9 class: chem p.4
balance & identify the reaction type
balance each equation and then identify the reaction type (combination, decomposition,
displacement, or double displacement).

1. ca + 2cl₂ → cacl₂

balanced equation: _______________
reaction type: _______________

1. kclo₃ → kcl + o₂

balanced equation: _______________
reaction type: _______________

1. mg + cuso₄ → mgso₄ + cu

balanced equation: _______________
reaction type: _______________

1. na₂co₃ + cacl₂ → caco₃ + nacl

balanced equation: _______________
reaction type: _______________

Explanation:

Step1: Check equation 1 balance

The given equation $\text{Ca} + 2\text{Cl}_2
ightarrow \text{CaCl}_2$ has unbalanced Cl atoms. Adjust coefficients to balance:
$\text{Ca} + \text{Cl}_2
ightarrow \text{CaCl}_2$
Classify reaction type: two substances form one product.

Step2: Balance equation 2

Given $\text{KClO}_3
ightarrow \text{KCl} + \text{O}_2$, balance O and K/Cl:
$2\text{KClO}_3
ightarrow 2\text{KCl} + 3\text{O}_2$
Classify reaction type: one substance breaks into two.

Step3: Check equation 3 balance

Given $\text{Mg} + \text{CuSO}_4
ightarrow \text{MgSO}_4 + \text{Cu}$, count atoms: all are balanced.
Classify reaction type: one element replaces another.

Step4: Balance equation 4

Given $\text{Na}_2\text{CO}_3 + \text{CaCl}_2
ightarrow \text{CaCO}_3 + \text{NaCl}$, balance Na and Cl:
$\text{Na}_2\text{CO}_3 + \text{CaCl}_2
ightarrow \text{CaCO}_3 + 2\text{NaCl}$
Classify reaction type: ions swap between two compounds.

Answer:

1. Balanced equation: $\boldsymbol{\text{Ca} + \text{Cl}_2

ightarrow \text{CaCl}_2}$
Reaction type: $\boldsymbol{\text{Combination}}$

1. Balanced equation: $\boldsymbol{2\text{KClO}_3

ightarrow 2\text{KCl} + 3\text{O}_2}$
Reaction type: $\boldsymbol{\text{Decomposition}}$

1. Balanced equation: $\boldsymbol{\text{Mg} + \text{CuSO}_4

ightarrow \text{MgSO}_4 + \text{Cu}}$
Reaction type: $\boldsymbol{\text{Displacement}}$

1. Balanced equation: $\boldsymbol{\text{Na}_2\text{CO}_3 + \text{CaCl}_2

ightarrow \text{CaCO}_3 + 2\text{NaCl}}$
Reaction type: $\boldsymbol{\text{Double displacement}}$