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o-17 0.0381 16.9991317 amu ( _3_ )(16.9991317 amu) = _4_ amu o-18 0.205…

Question

o-17 0.0381 16.9991317 amu ( _3_ )(16.9991317 amu) = _4_ amu
o-18 0.20514 17.9991611 amu ( _5_ )(17.9991611 amu) = _6_ amu
_7_ amu
first we need to convert the % abundance into abundance by dividing by 100.
thus, 99.7572% becomes:
99.7572
---------- = _8_
100
a. 15.9995
b. 15.9994791
c. 0.0020514
d. 0.000381
e. 0.997572
f. 99.7572.
g. 0.03692348
h. 0.0064767
i. 15.956079
j 1.5956079

Explanation:

Step1: Convert percentage to decimal for O - 17

Divide 0.0381 (which is already in decimal form, equivalent to 3.81%) by 100 to get 0.000381.

Step2: Calculate product for O - 17

Multiply 0.000381 by 16.9991317 amu. $0.000381\times16.9991317 = 0.0064767$ amu.

Step3: Convert percentage to decimal for O - 18

0.20514 (equivalent to 20.514%) is already in decimal form.

Step4: Calculate product for O - 18

Multiply 0.20514 by 17.9991611 amu. $0.20514\times17.9991611=3.692348$ amu.

Step5: Calculate the value for 99.7572% conversion

Divide 99.7572 by 100. $\frac{99.7572}{100}=0.997572$

Answer:

E. 0.997572, B. 15.9994791, D. 0.000381, H. 0.0064767, C. 0.0020514, G. 0.03692348, A. 15.9995