Question

part 1 (1 point) hydroxylamine (nh3o) is an intermediate in a variety of biological nitrification processes. to draw its lewis structure, you first need to know how many valence electrons it has. nh3o has valence electrons. part 2 (1 point) next you should decide how to arrange the atoms. based on the normal bonding patterns for n and o, which of the following options correctly describes how to arrange the atoms in nh3o? choose one or more: all the h atoms will be bonded to n. n will be bonded to o. both n and o have at least one h atom. all the h atoms are bonded to o.

Explanation:

Step1: Determine valence - electrons of each atom

N has 5 valence electrons, H has 1 valence electron, and O has 6 valence electrons. In \(NH_3O\), there is 1 N, 3 H, and 1 O. So the total number of valence electrons is \(5+(1\times3)+6 = 14\).

Step2: Analyze bonding patterns

N typically forms 3 bonds and has 1 lone - pair, and O typically forms 2 bonds and has 2 lone - pairs. In \(NH_3O\), the nitrogen atom is bonded to the oxygen atom. Also, nitrogen has 2 hydrogen atoms bonded to it and oxygen has 1 hydrogen atom bonded to it. So, N will be bonded to O and both N and O have at least one H atom.

Answer:

Part 1: 14
Part 2: N will be bonded to O; Both N and O have at least one H atom.