Question

part d
te
express your answer in condensed form in order of increasing orbital energy as a string without blshould be entered as he2s^22p^2.

Explanation:

Step1: Identify Ti's atomic number

Titanium (Ti) has an atomic number of 22, meaning it has 22 electrons.

Step2: Find noble gas core

The noble gas preceding Ti is Argon (Ar), which has 18 electrons.

Step3: Add remaining electrons

Subtract core electrons: $22 - 18 = 4$. These fill the $4s$ and $3d$ orbitals: $4s^23d^2$.

Step4: Condense with noble gas

Combine core and valence orbitals in energy order.

Step5: Identify Te's atomic number

Tellurium (Te) has an atomic number of 52, meaning it has 52 electrons.

Step6: Find noble gas core

The noble gas preceding Te is Krypton (Kr), which has 36 electrons.

Step7: Add remaining electrons

Subtract core electrons: $52 - 36 = 16$. These fill orbitals in order: $5s^24d^{10}5p^4$.

Step8: Condense with noble gas

Combine core and valence orbitals in energy order.

Answer:

Ti: $\text{[Ar]}4s^23d^2$
Te: $\text{[Kr]}5s^24d^{10}5p^4$