Question

part 1 of 2
what is the molarity of a solution prepared using the given amount of solute and total volume of solution?
5.1 mol of nacl in 4.70 l of solution. be sure your answer has the correct number of significant figures.
□ m nacl

Explanation:

Step1: Recall molarity formula

Molarity $M = \frac{\text{moles of solute}}{\text{volume of solution (L)}}$

Step2: Substitute given values

$M = \frac{5.1\ \text{mol}}{4.70\ \text{L}}$

Step3: Calculate and round sig figs

$M = 1.0851... \approx 1.1$ (2 significant figures, matching 5.1)

Answer:

1.1 M NaCl