Question

pentasilane (si₅h₁₂) is a liquid with a density of 0.827 g/cm³. it reacts with oxygen to give silicon dioxide (sio₂) and water. calculate the mass of water that would form if 24.1 cm³ of pentasilane reacted completely with excess oxygen. mass = g. 3 item attempts remaining. use the references to access important values if needed for this question.

Explanation:

Step1: Recall density - mass - volume formula

The formula for density ($
ho$), mass ($m$) and volume ($V$) is $
ho=\frac{m}{V}$. We can re - arrange it to find mass $m =
ho\times V$.

Step2: Substitute given values

We are given that $
ho = 0.827\ g/cm^{3}$ and $V=24.1\ cm^{3}$.
$m=0.827\ g/cm^{3}\times24.1\ cm^{3}$
$m = 0.827\times24.1\ g$
$m=19.9307\ g$

Answer:

$19.9\ g$ (rounded to one decimal place)