Question

period chemistry worksheet name

1. give the chemical symbol for each of the following ele - ments.

a. bromine c. mercury e. fluorine
b. bismuth d. vanadium f. calcium

1. give the chemical symbol for each of the following ele - ments.

a. silver c. cadmium e. tin
b. aluminium d. antimony f. arsenic

1. for the following processes that show the formation of ions, fill in the number of electrons that must be lost or gained to complete the process.

a. sr→sr²⁺ + ____ e⁻
b. se + ____ e⁻→se²⁻
c. fe→fe²⁺ + ____ e⁻
d. p + ____ e⁻→p³⁻
e. br + ____ e⁻→br⁻
f. au→au³⁺ + ____ e⁻

1. form the ionic compounds from the given anions and cations.

anions fe²⁺ al³⁺ hg²⁺ nh₄⁺ na⁺
oh⁻
cl⁻
so₄⁻
po₄⁻³

Explanation:

Step1: Find chemical symbols

a. Bromine: Br; c. Mercury: Hg; e. Fluorine: F; h. Bismuth: Bi; d. Vanadium: V; f. Calcium: Ca; for question 1. For question 2, a. Silver: Ag; c. Cadmium: Cd; e. Tin: Sn; h. Aluminium: Al; d. Antimony: Sb; f. Arsenic: As.

Step2: Determine electron - loss or gain

a. In $Sr
ightarrow Sr^{2 +}+2e^{-}$, strontium loses 2 electrons.
b. In $Se + 2e^{-}
ightarrow Se^{2 -}$, selenium gains 2 electrons.
c. In $Fe
ightarrow Fe^{2+}+2e^{-}$, iron loses 2 electrons; in $Fe
ightarrow Fe^{3+}+3e^{-}$, iron loses 3 electrons.
d. In $P + 3e^{-}
ightarrow P^{3 -}$, phosphorus gains 3 electrons.
e. In $Br+e^{-}
ightarrow Br^{-}$, bromine gains 1 electron.
f. In $Au
ightarrow Au^{3+}+3e^{-}$, gold loses 3 electrons.

Step3: Form ionic compounds

For $OH^{-}$:

• With $Fe^{2+}$: $Fe(OH)_2$; with $Al^{3+}$: $Al(OH)_3$; with $Hg^{2+}$: $Hg(OH)_2$; with $NH_4^{+}$: $NH_4OH$; with $Na^{+}$: $NaOH$.

For $Cl^{-}$:

• With $Fe^{2+}$: $FeCl_2$; with $Al^{3+}$: $AlCl_3$; with $Hg^{2+}$: $HgCl_2$; with $NH_4^{+}$: $NH_4Cl$; with $Na^{+}$: $NaCl$.

For $SO_4^{2 -}$:

• With $Fe^{2+}$: $FeSO_4$; with $Al^{3+}$: $Al_2(SO_4)_3$; with $Hg^{2+}$: $HgSO_4$; with $NH_4^{+}$: $(NH_4)_2SO_4$; with $Na^{+}$: $Na_2SO_4$.

For $PO_4^{3 -}$:

• With $Fe^{2+}$: $Fe_3(PO_4)_2$; with $Al^{3+}$: $AlPO_4$; with $Hg^{2+}$: $Hg_3(PO_4)_2$; with $NH_4^{+}$: $(NH_4)_3PO_4$; with $Na^{+}$: $Na_3PO_4$.

Answer:

1. a. Br; c. Hg; e. F; h. Bi; d. V; f. Ca
2. a. Ag; c. Cd; e. Sn; h. Al; d. Sb; f. As
3. a. 2; b. 2; c. 2, 3; d. 3; e. 1; f. 3

4.

Anion/Cation	$Fe^{2+}$	$Al^{3+}$	$Hg^{2+}$	$NH_4^{+}$	$Na^{+}$
$Cl^{-}$	$FeCl_2$	$AlCl_3$	$HgCl_2$	$NH_4Cl$	$NaCl$
$SO_4^{2 -}$	$FeSO_4$	$Al_2(SO_4)_3$	$HgSO_4$	$(NH_4)_2SO_4$	$Na_2SO_4$
$PO_4^{3 -}$	$Fe_3(PO_4)_2$	$AlPO_4$	$Hg_3(PO_4)_2$	$(NH_4)_3PO_4$	$Na_3PO_4$