Question

1. plants and animals depend on glucose as an energy source. calculate the number of moles of carbon in 1.25 mol glucose. (0.5 points) *

7.50 mol
2.50 mol
8.25 mol
5.25 mol

1. iron(iii) sulfate is sometimes used in the water purification process. determine the number of moles of sulfate ions present in 3.00 mol of iron(iii) sulfate (0.5 points) *

8.50 mol
10.9 mol
12.5 mol
9.00 mol

Explanation:

Question 3

Step1: Recall glucose formula

Glucose has the formula $C_6H_{12}O_6$, so 1 mol glucose has 6 mol C.

Step2: Calculate moles of C

Moles of C = moles of glucose × 6 = $1.25\ \text{mol} × 6 = 7.50\ \text{mol}$

Step1: Recall Iron(III) sulfate formula

Iron(III) sulfate is $Fe_2(SO_4)_3$, so 1 mol $Fe_2(SO_4)_3$ has 3 mol $SO_4^{2-}$ (sulfate ions).

Step2: Calculate moles of sulfate ions

Moles of sulfate = moles of $Fe_2(SO_4)_3$ × 3 = $3.00\ \text{mol} × 3 = 9.00\ \text{mol}$

Answer:

7.50 mol (the option with "7.50 mol")

Question 4