Question

portions of orbital diagrams representing the ground-state electron configurations of certain elements are shown here:
part 1 of 2
which violate the pauli exclusion principle? check all that apply.
orbital diagram options with checkboxes, followed by none of the above

Explanation:

The Pauli Exclusion Principle states that no two electrons in an atom can have the same set of four quantum numbers. In terms of orbital diagrams, this means that each orbital (represented by a box) can hold a maximum of two electrons, and these two electrons must have opposite spins (represented by up and down arrows, e.g., $\uparrow$ and $\downarrow$). If an orbital has more than two electrons or two electrons with the same spin, it violates the Pauli Exclusion Principle.

Step 1: Analyze the first orbital diagram

The first diagram has orbitals with various electron configurations. Let's check each orbital:

• The first three orbitals have one electron (spin up, $\uparrow$).
• The fourth orbital has one electron (spin down, $\downarrow$).
• The fifth orbital has two electrons (one up and one down, $\uparrow\downarrow$).

No orbital has more than two electrons or two electrons with the same spin. So, this does not violate the Pauli Exclusion Principle.

Step 2: Analyze the second orbital diagram

• The first two orbitals have one electron (spin up, $\uparrow$).
• The third orbital has one electron (spin down, $\downarrow$).
• The fourth and fifth orbitals have one electron (spin up, $\uparrow$).

No orbital has more than two electrons or two electrons with the same spin. So, this does not violate the Pauli Exclusion Principle.

Step 3: Analyze the third orbital diagram

• The first orbital has two electrons with the same spin (both up, $\uparrow\uparrow$). This violates the Pauli Exclusion Principle because an orbital can hold at most two electrons with opposite spins.
• The second orbital has two electrons with opposite spins ($\uparrow\downarrow$), which is allowed.
• The remaining orbitals have one electron each (spin up, $\uparrow$), which is allowed.

So, this orbital diagram violates the Pauli Exclusion Principle.

Step 4: Analyze the fourth orbital diagram

• The first two orbitals have one electron (spin up, $\uparrow$).
• The third orbital has two electrons with opposite spins ($\uparrow\downarrow$), which is allowed.

No orbital has more than two electrons or two electrons with the same spin. So, this does not violate the Pauli Exclusion Principle.

Answer:

The orbital diagram with $\boxed{11\ 1\downarrow\ 1\ 1\ 1}$ (the third one) violates the Pauli exclusion principle.