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Question
problem 1
in this net, the two triangles are right triangles. all quadrilaterals are rectangles. what is its surface area in square units? show your reasoning.
Step1: Identify shapes and areas
- Two right triangles: Area of one triangle is $\frac{1}{2} \times 8 \times 6$. Two triangles: $2 \times \frac{1}{2} \times 8 \times 6 = 48$.
- Three rectangles:
- First rectangle: $10 \times 5$, area = $50$.
- Middle rectangle: $8 \times 5$, area = $40$.
- Third rectangle: $6 \times 5$, area = $30$.
Step2: Sum all areas
Total surface area = $48 + 50 + 40 + 30$.
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