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problem 1 in this net, the two triangles are right triangles. all quadr…

Question

problem 1
in this net, the two triangles are right triangles. all quadrilaterals are rectangles. what is its surface area in square units? show your reasoning.

Explanation:

Step1: Identify shapes and areas

  • Two right triangles: Area of one triangle is $\frac{1}{2} \times 8 \times 6$. Two triangles: $2 \times \frac{1}{2} \times 8 \times 6 = 48$.
  • Three rectangles:
  • First rectangle: $10 \times 5$, area = $50$.
  • Middle rectangle: $8 \times 5$, area = $40$.
  • Third rectangle: $6 \times 5$, area = $30$.

Step2: Sum all areas

Total surface area = $48 + 50 + 40 + 30$.

Answer:

168