Question

provide the atomic symbol of an isotope that has eight protons, eight neutrons and ten electrons. question 8 provide the atomic symbol of an isotope that has one proton, one neutron and no electrons.

Explanation:

Step1: Determine atomic number (Z)

The number of protons gives the atomic number. For the first - case, Z = 8 (since there are 8 protons), which corresponds to oxygen (O). For the second - case, Z = 1 (since there is 1 proton), which corresponds to hydrogen (H).

Step2: Calculate mass number (A)

The mass number is the sum of protons and neutrons. In the first case, A=8 + 8=16. In the second case, A = 1+1 = 2.

Step3: Determine the charge

In the first case, there are 10 electrons and 8 protons, so the charge is 8 - 10=- 2. In the second case, there are 0 electrons and 1 proton, so the charge is + 1.

Step4: Write the atomic symbol

The atomic symbol is written as $_{Z}^{A}X^{n\pm}$, where X is the chemical symbol, Z is the atomic number, A is the mass number, and $n\pm$ is the charge.
For the first isotope: $_{8}^{16}O^{2 - }$
For the second isotope: $_{1}^{2}H^{+}$

Answer:

$_{8}^{16}O^{2 - }$
$_{1}^{2}H^{+}$