Question

question 10 points 1 which of the following pairs would most likely form a ternary ionic compound? 1. calcium and fluorine 2. sodium and sulfate 3. carbon and carbonate 4. calcium and sulfate ○ 2 ○ 3 ○ 1 and 3 ○ 4 and 2

Explanation:

A ternary ionic compound contains three different elements (usually a metal cation and a polyatomic anion). Let's analyze each pair:

1. Calcium (Ca) and fluorine (F) form CaF₂, a binary ionic compound (only two elements), so not ternary.
2. Sodium (Na) and sulfate (\(SO_4^{2-}\)): Sodium is a metal cation, sulfate is a polyatomic anion. The compound formed is \(Na_2SO_4\) (sodium sulfate), which has three elements (Na, S, O) – a ternary ionic compound.
3. Carbon (C) is a non - metal and not a typical cation - forming species in ionic compounds with carbonate (\(CO_3^{2-}\)) in the way required for a stable ionic compound. Carbon doesn't form a cation here to combine with carbonate to form a stable ionic compound.
4. Calcium (Ca) and sulfate (\(SO_4^{2-}\)): Calcium is a metal cation, sulfate is a polyatomic anion. The compound formed is \(CaSO_4\) (calcium sulfate), which has three elements (Ca, S, O) – a ternary ionic compound.

So pairs 2 (Sodium and sulfate) and 4 (Calcium and sulfate) form ternary ionic compounds.

Answer:

4 and 2 (Calcium and sulfate, Sodium and sulfate)