Question

question 11 of 12 what nacl concentration results when 294 ml of a 0.780 m nacl solution is mixed with 447 ml of a 0.340 m nacl solution? concentration: m

Explanation:

Step1: Calculate moles in first solution

Use $n = M\times V$ (where $n$ is moles, $M$ is molarity, $V$ is volume in L). First volume $V_1=294\ mL = 0.294\ L$ and $M_1 = 0.780\ M$. So $n_1 = M_1\times V_1=0.780\times0.294 = 0.22932\ mol$.

Step2: Calculate moles in second solution

Second volume $V_2 = 447\ mL=0.447\ L$ and $M_2 = 0.340\ M$. So $n_2 = M_2\times V_2=0.340\times0.447 = 0.15198\ mol$.

Step3: Calculate total moles

$n_{total}=n_1 + n_2=0.22932+ 0.15198=0.3813\ mol$.

Step4: Calculate total volume

$V_{total}=V_1 + V_2=0.294 + 0.447=0.741\ L$.

Step5: Calculate final molarity

Use $M=\frac{n}{V}$, so $M_{final}=\frac{n_{total}}{V_{total}}=\frac{0.3813}{0.741}\approx0.515\ M$.

Answer:

$0.515$